Question 1070200
What is the value for n 
{{{3(n + 1/3) = 2}}} 
distribute the 3
{{{3n + 3/3 = 2}}}
which is
3n + 1 = 2
3n = 2 - 1
3n = 1
n = {{{1/3}}}
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See if that checks out in the original equation
{{{3(1/3 + 1/3) = 2}}}
{{{3(2/3) = 2}}}
cancel 3
2 = 2