Question 262337
The points(-1,-7) and (5,10) are the endpoints of the diameter of a circle. Graph the circle.  Find an equation of the circle.
   Cordinates of Midpoint of diameter of a circle=((x1 x2)/2, (y1 y2)/2): ((-1  5)/2, (-7 10)/2)=(2, 3/2). Where a=2 and b=3/2, radius r^2 =(a-x1)^2 (b-x2)^2: r^2=(2--1)^2 (3/2--7)^2, r=9.01. Eqn of circle: (x-a)^2 (y-b)^2=r^2: (x-2)^2 (y-3/2)^2=81.25.