Question 94103
Let w be the width of the rectangle and l be the lenght. 


Given that w = w and lenght equals three more than w. So l = 3 + w 


We know that the perimeter is given by  2l + 2w = P 


Substituting for the values of l and w, we get: 


2(3 + w) + 2w = 24 


6 + 2w + 2w = 24 


6 + 4w = 24 


4w = 24 - 6 


4w = 18 


==>  {{{w = (18/4)}}} 


==> {{{w = (9/2)}}} 


Thsi gives the width of the rectangle. 


Now the length is got by substituing it in l = 3 + w 


{{{l = 3 + (9/2)}}}



{{{ l = 15/2}}} 



This gives the lenght..


The width and the lenght of the rectangle can be cross verified by substituting it back in the perimeter equation. 


{{{2(15/2) + 2(9/2)}}} 


=  15 + 9  


= 24  


= RHS 


Hence, the solution is correct..!!


Happy calculating..


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Regards

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