Question 1070069
<pre>
y is constantly 0 because those absolute values are equal. 
That's because what's between the first pair of absolute 
value bars is -1 times what's between the second pair.  So 
it's just equivalent to y = 0 for all values.  It is not 
necessary to take those special cases indicated.  You can 
show y = 0 for ALL values of x this way:

y = |-2x+5| - |2x-5|
y = |-1(2x-5)| - |2x-5|
y = |-1||2x-5| - |2x-5|
y = 1|2x-5| - |2x-5|
y = |2x-5| - |2x-5|
y = 0

Edwin</pre>