Question 1069956
Using Cramer's rule,
{{{A=(matrix(3,3,
4,-4,4,
4,1,-2,
-3,-3,-4))}}}
{{{abs(A)=-164}}}
.
.
.
{{{A[x]=(matrix(3,3,
4,-4,4,
5,1,-2,
-16,-3,-4))}}}
{{{abs(A[x])=-164}}}
.
.
.
{{{A[y]=(matrix(3,3,
4,4,4,
4,5,-2,
-3,-16,-4))}}}
{{{abs(A[y])=-492}}}
.
.
.
{{{A[z]=(matrix(3,3,
4,-4,4,
4,1,5,
-3,-3,-16))}}}
{{{abs(A[z])=-164}}}
.
.
.
{{{x=abs(A[x])/abs(A)=-164/-164=1}}}
{{{y=abs(A[y])/abs(A)=-492/-164=3}}}
{{{z=abs(A[z])/abs(A)=-164/-164=1}}}