Question 1069948
{{{y=3x+12}}}
Interchange x and y,
{{{x=3y+12}}}
Solve for y.
{{{3y=x-12}}}
{{{y=(x-12)/3}}}
This new y is the inverse of the original function,
{{{g(x)=(x-12)/3}}}
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{{{f(g)=3g+12=3((x-12)/3)+12=x-12+12=x}}}
{{{g(f)=(f-12)/3=(3x+12-12)/3=(3x)/3=x}}}
f and g are inverses.
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{{{f(g(-2))=-2}}}
As shown in b.
Domain is all real numbers.
Range is all real numbers.