Question 1069914
there are 200 dogs in the compound.
99% of them are brown.
that means there are 198 brown dogs and 2 dogs that are not brown.


let x equal the number of brown dogs that are removed.


if you remove x brown dogs, then you are also removing x dogs from the total.


i believe your formula should be:


198 - x = .98 * (200 - x).


simplify this to get 198 - x = 196 - .98 * x


subtract 196 from both sides of this equation and add x to both sides of this equation to get:


2 = .02 * x


divide both sides of this equation by .02 to get:


2/.02 = x


solve for x to get x 2/.02 = 200/2 = 100.


you would have to remove 100 dogs to make the percent equal to 98.


198 - 100 = 98.


200 - 100 = 100


98/100 = .98 * 100 = 98%.


as strange as it sounds, you would have to remove 100 brown dogs to make the percentage of brown dogs equal to 98%.


this is because, every time you remove a brown dog, the total number of dogs is reduced by 1.


to see if this makes sense, try some numbers less than 100.


if you remove 2 brown dogs, then you have 196 out of a total of 198.
the percentage is 98.9.....

if you remove 50 brown dogs, then you have 148 out of a total of 150.
the percentage is 98.67.


if you remove 100 brown dogs, then you have 98 / 100 = 98%.


note that the number of dogs that are not brown never changes.


you still have 2 dogs that are not brown.


2 / 100 = .02 = 2%.


this means that the percent of brown dogs is 98%.