Question 1069749
Let east be positive x, north positive y.
Starting at (0,0).
(0,0)+(0,3)=(0,3)
(0,3)+(8,0)=(8,3)
(8,3)+(0,3)=(8,6)
So he traveled a total of {{{3+8+3=14}}}{{{km}}}
Use the distance formula,
{{{D^2=(8-0)^2+(6-0)^2}}}
{{{D^2=64+36}}}
{{{D^2=100}}}
{{{D=10}}}{{{km}}}
So he could save 4 km.