Question 1069711
{{{P(X)=C(6,X)*(1/2)^X*(1/2)^(6-X)}}}
{{{P(X)=C(6,X)(1/2)^6}}}
{{{P(X)=C(6,X)/64}}}
So then,
{{{P(0)=1/64}}}
{{{P(1)=6/64}}}
{{{P(2)=15/64}}}
{{{P(3)=20/64}}}<--- You had 40, that was your mistake.
{{{P(4)=15/64}}}
{{{P(5)=6/64}}}
{{{P(6)=1/64}}}
At least two means two through six,
{{{P=(15+20+15+6+1)/64}}}
{{{P=57/64}}}