<PRE><B>Question 1069398</B>
Suppose Z is a standard normal random variable. 
If P(-z &lt; Z &lt; z) = 0.5588, find z. 
Find P( -2.46 &lt; Z &lt; -0.16)
Some did it but wasn&#39;t right
Please help
Thank you so much
&lt;pre&gt;As P(- z &lt; Z &lt; z) = 0.5588, .5588 is the center interval beneath the bell curve
Therefore, to the left of the P(Z), probability = 1 - .5588, or .4412
This probability represents the TOTAL probabilities of the left and right tails
We now take the AVERAGE of this probability to get {{{matrix(1,3, .4412/2, &quot;=&quot;, .2206)}}}
Using a calculator, excel, or other applications, you&#39;ll find that the z-score that represents a probability (to the left of the curve) of .2206 is: - 0.77,
which means that: {{{highlight_green(matrix(1,17, &quot;P(-&quot;, z, &quot;&lt;&quot;, Z, &quot;&lt;&quot;, &quot;z)&quot;, &quot;=&quot;, .5588, &quot;becomes:&quot;, &quot;P(-&quot;, 0.77, &quot;&lt;&quot;, Z, &quot;&lt;&quot;, &quot;0.77)&quot;, &quot;=&quot;, .5587))}}}. This is close enough.</PRE>