Question 1069535
It is 1- probability 1 unit is good or 0 units are good.
p=(1/2)
four defective is (6/12)(5/11)(4/10)(3/9)=360/11880=0.0303
three defective is 4(6/12)(5/11)(4/10)(6/9)=2880/11880=0.2424
That is 0.2727
probability at least two are good is 1-0.2727=0.7273 ANSWER
(probability two defective is (6/12)(5/11(6/10)(5/9)*6=5400/11880=0.4545)