Question 1069496
{{{x^2=y+1}}}
{{{y=x^2+1}}}
Parabola
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{{{4x^2+4x+y^2=0}}}
{{{4(x^2+x)+y^2=0}}}
{{{(x^2+x)+y^2/4=0}}}
{{{(x^2+x+A)+y^2/4=A}}}
{{{(x+b)^2/a^2+y^2/4=1}}}
Ellipse, a,b,and A are stand-ins for non-zero constants needed to complete the square and show that the equation is an ellipse.