Question 1069444
(log3 (6))/3 + (log3 (11))/3 + (log3 (5))/3

I am supposed to condense, but we never talked about working with an expression "all over" another number. Is it the same as 1/3 (log3 6) + 1/3 (log3 11) + 1/3 (log3 5)?
log(6)/3 + log(11)/3 + log(5)/3  --- all base 3
= (log(6) + log(11) + log(5))/3

= log(6*11*5)/3
= {{{log(3,330)/3}}}
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When this assignment was introduced, we had not talked about changing log bases or anything like that, but is that involved?
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You can change the base or not.