Question 1069343
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A jar of 45 coins consists only of nickels, dimes, and quarters, with a face value of $5.90. 
The numbers of nickels and dimes together exceed the number of quarters by 19. How many quarters are in the jar?
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<pre>
N + D + Q = 45,    (1)
N + D - Q = 19.    (2)

Subtract eq(2) from eq(1) (both sides). You will get

2Q = 45 - 19 = 26   --->  Q = {{{26/2}}} = 13.

<U>Answer</U>. 13 quarters.
</pre>

The info about "face value" is excessive, unnecessary and serves for only one goal: to confuse the  reader.


It is not used in the solution.