Question 1069316

I have to solve this factoring problem :
6x^4-10x^3-6x^2
the # after the ^ is the exponents 
I found a GCF of 2x^2 and left off at:
2x^2(3x^2-5x-3) 
I did x+x=b which is -5
and x*x=ac which is -9 
so what two numbers would added give me -5 but multiplied give me -9?
Thats as far as i got. Please help me 
Thanks 
<pre>Good job!! You're correct up to here =======> {{{2x^2(3x^2 - 5x - 3)}}}
I see you tried to find factors with a product of - 9, and that sum to - 5 (ac method).
Those integers do not exist, so this is where the factoring ends, as it cannot be factored further.