Question 1069227
Let {{{ d }}} = the one-way distance he rowed in miles
Let {{{ t }}} = time in hrs to row upstream
{{{ 55 - t }}} = time in hrs to row downstream
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Equation for going upstream
(1) {{{ d = 22t }}}
Equation for going downstream
(2) {{{ d = 88*( 55 - t ) }}}
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(2) {{{ d = 4840 - 88t }}}
Substitue (1) into (2)
(2) {{{ 22t = 4840 - 88t }}}
(2) {{{ 110t = 4840 }}}
(2) {{{ t = 44 }}}
and
{{{ 55 - t = 55 - 44 }}}
{{{ 55 - t = 11 }}}
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(1) {{{ d = 22t }}}
(1) {{{ d = 22*44 }}}
(1) {{{ d = 968 }}}
and
{{{ 2*968 = 1936 }}}
He rowed 1,936 miles
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check:
(2) {{{ d = 88*( 55 - t ) }}}
(2) {{{ 968 = 88*( 55 - 44 ) }}}
(2) {{{ 968 = 88*11 }}}
(2) {{{ 968 = 968 }}}
OK