Question 1069198
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<pre>
2x +  5y = 4,    (1)
4x + 10y = 1.    (2)

Multiply the first equation by 2 (both sides). You will get an equivalent system

4x + 10y = 8,    (1')
4x + 10y = 1.    (2')

These equations have identical left sides, but different right sides.

It implies, that the system (1'),(2') has no solutions.
</pre>

<U>Answer</U>. There are NO SOLUTIONS.


See the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =http://www.algebra.com/algebra/homework/coordinate/lessons/Geom-interpret-of-the-lin-system-of-two-eqns-with-two-unknowns.lesson>Geometric interpretation of the linear system of two equations in two unknowns</A> 

in this site.


Also, you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic "<U>Systems of two linear equations in two unknowns</U>".