Question 1069137

Please explain how to solve
Sqrt 5x+1-4 = 0.  

I get the following;
sqrt 5x+1-4=0
sqrt 5x-3=0
5x-3=0^2
5x-3=0
5x-3+3=0+3
5x=3
5x/5 = 3/5
x=3/5

Thank you.
<pre>No-one can unless you can state whether it's: {{{matrix(1,3, sqrt(5x + 1) - 4 = 0, or, sqrt(5x + 1 - 4) = 0)}}}. 
I kind of doubt it's: {{{sqrt(5x) + 1 - 4 = 0}}}