Question 93972
In a right triangle 1 would be the opposite and 5 the hypotenuse.
{{{a^2+b^2=c^2}}}
{{{1^2+b^2=5^2}}}
{{{b^2=25-1=24}}}
{{{b=sqrt(24)=sqrt(4*6)=2sqrt(6)}}} the adjacent side
The secant = hypotenuse/adjacent = {{{5/2sqrt(6)}}}
Multiply top and bottom by {{{sqrt(6)}}}to get the square root out of the denominator and you get {{{5sqrt(6)/12}}}

Ed Jones