Question 1068766
5y -3x + 1 = 0
5y = 3x - 1
y = (3/5)x - (1/5)
Slope = 3/5
In quadrant III, tan θ is positive.
tan θ = 3/5
θ is the angle of a right triangle, whose
opposite O = 3
adjacent A = 5
Therefore hypotenuse H = {{{sqrt(3^2+5^2)=sqrt(34)}}}
sin θ = {{{-O/H = -3/sqrt(34)}}}
cos θ = {{{-A/H = -5/sqrt(34)}}}
csc θ = 1/sin θ = {{{-sqrt(34)/3}}}
sec θ = 1/cos θ = {{{-sqrt(34)/5}}}
cot θ = 1/tan θ = {{{5/3}}}

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