Question 1068793
The 5 songs of Adele can be arranged in 5! = 120 ways
In any arrangement of the 5 songs of Adele, there are 6 slots left: 4 in between, 1 in the beginning and 1 at the end.
If Lady Gaga's songs are inserted in these 6 spaces, then no two Lady Gaga's songs are consecutive.

3 songs of Lady Gaga can be arranged in 6 slots in 
6P3 = 6!/(6-3)! = 6!/3! = 120 ways

Total number of ways = 120 x 120 = 14400 (Answer)
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