Question 1068947
Let me guess, that you have  log(4,(x^2-6x))=2, or as rendered, {{{log(4,(x^2-6x))=2}}}.  If it is this, then your first step is wrong.


Put into exponential form, using base of 4:


{{{4^2=x^2-6x}}}

and then

{{{x^2-6x=16}}}

{{{x^2-6x-16=0}}}, and you can try solving this quadratic equation.