Question 1068820
{{{-5y(2y-2)+7y=9+2(6y-4)}}}
{{{-10y^2+10y+7y=9+12y-8}}}
{{{-10y^2+5y-1=0}}}
Using the quadratic formula,
{{{y = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{y = (-5 +- sqrt( 5^2-4*(-10)*(-1) ))/(2*(-10)) }}} 
{{{y = (-5 +- sqrt( 25-40 ))/(-20) }}} 
{{{highlight(y = (5 +- sqrt(15)i)/(20)) }}}