Question 1068763
{{{P(S)=3/4}}} Success probability
{{{P(F)=1/4}}} Failure probability
a) {{{P=P(S)P(S)=(3/4)(3/4)=9/16}}}
b) {{{P=P(F)P(F)=(1/4)(1/4)=1/16}}}
At least 1 means "not missing both times",
c) {{{P=1-1/16=15/16}}}