Question 1068754
n, any integer

Four consecutive integers: n, n+1, n+2, n+3


{{{2(n+3)=-25+(n+2)/2}}}


{{{4(n+3)=-50+n+2}}}

{{{4n+12=n-48}}}

{{{3n=-48-12}}}

{{{3n=-60}}}

{{{highlight(n=-20)}}}


The consecutive integers are  -20, -19, -18, -17.