Question 1068750
x^2+4x+2=0 has roots  {{{(-4-sqrt(16-4*2))/2}}} and {{{(-4+sqrt(16-4*2))/2}}};

or

{{{-2-sqrt(2)}}} and {{{-2+sqrt(2)}}}.


To make the equation whose roots are the squares of each of those,
the new roots would be {{{6+4*sqrt(2)}}} and {{{6-4*sqrt(2)}}}.
THe equation starts as  {{{(x-(6+4sqrt(2)))(x-(6-4*sqrt(2)))=0}}}.  Then one more small step.