Question 1068781
1/1===-2===-5===6
=1====-1===-6===0
(x-1)(x^2-x-6)=0;(x-1)(x-3)(x+2)=0 roots are 1,3,-2
{{{graph(300,300,-10,10,-10,10,x^3-2x^2-5x+6)}}}
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1/3===2===-8===3
=3===5===-3===0
(x-1)(3x^2+5x-3)=0; roots are 1,(1/6)(-5+/- sqrt(61))
{{{graph(300,300,-10,10,-10,10,3x^3+2x^2-8x+3)}}}
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