Question 93844
<pre><b>
{{{(3b)/5 + (2b - 5)/3 = -4}}}

Put parentheses around all the terms:

{{{((3b)/5) + ((2b - 5)/3) = (-4)}}}

The LCD is 15 so multiply every term by 15

{{{15((3b)/5) + 15((2b - 5)/3) = 15(-4)}}}

On the first term the 5 cancels into the 15 giving 3
On the second term the 3 cancels into the 15 giving 5
On the right we get -60

{{{3(3b) + 5(2b-5) = -60}}}

{{{9b + 10b - 25 = -60}}}

{{{19b - 25 = -60}}}

{{{19b = -60+25}}}

{{{19b = -35}}}

{{{b = -35/19}}}

Edwin</pre>