Question 1068589
A bag contains 8 apples, 5 are eating apples and 3 are cooking apples. 
If 2 apples are drawn without replacement.
Find the probability that 
A) the first apple is an eating apple and the second apple is a cooking apple
Ans: (5/8)(3/7) = 15/56
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B)one of the apples is an eating apple.
I'll assume you mean "exactly one of the apples is an eating apple".
Ans: (5/8)(3/7)+(3/8)(5/7) = (15/56)+(15/56) = 30/56
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Cheers,
Stan H.
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