Question 93861
Question:

The sum of two numbers is 43.  The second is 1 more than 2 times the first.  What are the two numbers?  

I got 2x + y + 1 = 43 as the equation and x = 22 and y = 21.  Is this correct or did I mess this up?  Thanks for your help in advance. 

Answer:

 Suppose the first  number = x

 
 Two times the first number = 2x


 Second number is 1 more than two times the first....


 
 so, second number(y)  = 2x + 1


 Given that sum  of these numbers = 43



 ==> x + 2x + 1 = 43


==> 3x + 1 = 43


==> 3x = 42



==> x = {{{42/3}}}



==> x = 14

There fore, y = 2x + 1 = 2*14 + 1 = 28 + 1 = 29


So,  first number = {{{14}}} and


     
     second number = {{{29}}}


Hope you found the explanation useful.


The answer you have got is not correct.  Their sum is 43  but second number is not one more than two times the first.

Hope you found the mistake you have committed.



Regards.



Praseena.