Question 1068472
You should use parentheses to clarify what you mean.
(x+2)/(x+4)-(x-1)/(x+6)
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Find a common denominator,
{{{(x+2)/(x+4)-(x-1)/(x+6)=((x+2)/(x+4))((x+6)/(x+6))-((x-1)/(x+6))((x+4)/(x+4))}}}
{{{(x+2)/(x+4)-(x-1)/(x+6)=(x^2+8x+12)/((x+4)(x+6))-(x^2+3x-4)/((x+6)(x+4))}}}
{{{(x+2)/(x+4)-(x-1)/(x+6)=(x^2+8x+12-x^2-3x+4)/((x+6)(x+4))}}}
{{{(x+2)/(x+4)-(x-1)/(x+6)=highlight((5x+16)/((x+6)(x+4)))}}}