Question 1068432
{{{ 12 - 2 = 10 }}} hrs is the time for a
round trip by X
{{{ 10/2 = 5 }}} hrs is the one-way time for X
{{{ 300/5 = 60 }}} km/hr is speed for X
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In {{{ 10 }}} hrs, X has been traveling for {{{ 10 - 2 = 8 }}}
hrs, so X is {{{ 60*( 8-5 ) =180 }}} km from B
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So now Y is at A and X is {{{ 300 - 180 = 120 }}} km
from Y and they are headed toward each other at {{{ 60 }}} km/hr
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Think of this as one of them standing still and the other moving
at the sum of their speeds
{{{ 120 = ( 60 + 60 )*t }}}
{{{ 120 = 120t }}}
{{{ t = 1 }}} hr
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In {{{ 1 }}} hr, Y travels {{{ 60*1 = 60 }}} mi
and meets X
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If X departed at 8:00 AM, then {{{ 10 + 1 = 11 }}} hrs later is
7:00 PM when trains meet ( 1 hr less than 12 hrs later )
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DEFINITELY get another opinion on this.
I could easily mess this up.