Question 1068201
1.{{{A+B+C=8500}}}
2.{{{(2/100)A+(3/100)B+(6/100)C=380}}}
3.{{{C=A+B}}}
From 2,
{{{2A+3B+6C=38000}}}
Substituting from 3,
{{{2A+3B+6A+6B=38000}}}
4.{{{8A+9B=38000}}}
Substituting from 3 into 1,
{{{A+B+A+B=8500}}}
{{{2A+2B=8500}}}
5.{{{8A+8B=34000}}}
Now subtract 5 from 4,
{{{8A+9B-8A-8B=38000-34000}}}
{{{B=4000}}}
Then,
{{{2A+2(4000)=8500}}}
{{{2A=500}}}
{{{A=250}}}
and
{{{C=A+B}}}
{{{C=250+4000}}}
{{{C=4250}}}