Question 1068229
8a+3c+4p = 54 
8a+7c+9p = 92 
2a+5c+6p = 52 
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1) Rearrange:
2a+5c+6p = 52
8a+7c+9p = 92 
8a+3c+4p = 54 
2) Multiply all terms in the 1st equation times -4 and add to the second equation, and you get:
2a+5c+6p = 52
. -13c-15p = -116
8a+3c+4p = 54
3) Multiply the second equation times -4 and add to the third equation to get:
2a+5c+6p = 52
. -13c-15p = -116
. -17a-20p = -154
4) Multiply the 2nd equation times -17/13 and add the result to the third equation, and now we have:
2a+5c+6p = 52
. -13c-15p = -116
. . . -5/13p = -30/13
Solve for p:
-5/13p = -30/13; p = -30/13*-13/5 = -30/-5 = 6 So now we know that p = 6 
-13c-15(6) = -116; -13c = -26; c = 2
8a+3c+4p = 54 
8a+3(2)+4(6) = 54
8a = 24
a = 3
So there you have it:
apples: 3
cherries: 2
pears: 6