Question 1068041
Let's call them A, B, and C.
{{{B=5+3A}}}
{{{A+B+C=55}}}
Substituting to find C.
{{{A+(5+3A)+C=55}}}
{{{4A+5+C=55}}}
{{{C=50-4A}}}
So then,
{{{P=A*B*C}}}
{{{P=A(5+3A)(50-4A)}}}
{{{P=(5A+3A^2)(50-4A)}}}
{{{P=250A-20A^2+150A^2-12A^3}}}
{{{P=-12A^3+130A^2+250A}}}