Question 1068046
Zero.
Using the law of sines,
{{{sin(A)/a=sin(B)/b}}}
{{{sin(85)/8=sin(B)/22}}}
{{{sin(B)=(22/8)sin(85)}}}
{{{sin(B)=(11/4)sin(85)}}}
Since {{{sin(85)}}} is close to 1, sin(B) would be out of range for the sine function so this triangle cannot exist,