Question 1067866


Problem Page
Keisha drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 
6
 hours. When Keisha drove home, there was no traffic and the trip only took 
4
 hours. If her average rate was 
22
 miles per hour faster on the trip home, how far away does Keisha live from the mountains?
<pre>Let the distance to the mountains be D
Then speed to the mountains = {{{D/6}}}
Speed on return trip = {{{D/4}}}
We then get the following SPEED equation: {{{D/6 = D/4 - 22}}}
Solve this to get a distance of: {{{highlight_green(matrix(1,2, 264, miles))}}}
That's all...nothing CONFUSING and/or COMPLEX!