Question 1067658
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A person has *[tex \Large P] currency units invested in 2 accounts.


One account earns *[tex \Large r_1] percent interest, and the other account earns *[tex \Large r_2] percent interest.


The two accounts earn a total of *[tex \Large I] interest in one year.


How much is invested in each account?


Let *[tex \Large x] be the amount invested at *[tex \Large r_1] percent.  Then the amount invested at *[tex \Large r_2] percent is *[tex \Large P\ -\ x], and:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{r_1}{100}x\ +\ \frac{r_2}{100}\left(P\ -\ x\right)\ =\ I]


Solve for *[tex \Large x], then calculate *[tex \Large P\ -\ x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

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