Question 1067865
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There are 8 ways to choose the first number (2 through 9).  For each of these ways to choose the first number there are 9 ways to choose the second number (0 through 9 except the first number chosen).  So there are 72 ways to choose the first two numbers.  Then, for each of those 72 ways to choose the first two numbers, there are 8 ways to choose the third number (0 through 9 except the first two numbers chosen), and so on.  In sum:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  8\ \times\ 9\ \times\ 8\ \times\ 7\ \times\ 6\ \times\ 5\ \times\ 4]


You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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