Question 93725
A plane took 1 hr longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion, what was the flying time for the second part of the trip?
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Let's just reason it out:
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The problem requests the flying time of the 2nd part, therefore:
Let x = time for the 2nd part of the trip
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It said,
"plane took 1 hr longer to travel 560 miles on the first portion of a flight::
therefore:
(x + 1) = time for the 1st part of the trip
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Speed was given as the same for each portion, so we can write a speed equation:
Speed = Dist/time
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1st part speed = 2nd part speed
{{{560/((x+1))}}} = {{{480/x}}}
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Cross multiply and we have:
560x = 480(x+1)
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560x = 480x + 480
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560x - 480x = 480
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80x = 480
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x = 480/80
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x = 6 hrs is the time of the 2nd part
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Check our solution to find out if, indeed, the speeds are the same.
1st part took 1 hr longer, 7 hrs.
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560/7 = 480/6
 80   = 80; confirms our solution
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Did this make sense to you? Any questions?