<PRE><B>Question 1067762</B>
 12x^3-20x^2-8x 
4x can be divided out
4x(3x^2-5x-2)=4x(3x+1)(x-2)
4x*(3x^2-6x+x-2)=12x^3-24x^2+4x^2-8x
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 42x^2-23x-5
divide 42 from first and multiply last term by 42
x^2-23x-210, which factors into (x+7)(x-30)
divide those by 42 and reduce completely
(x+7/42)(x-30/42)=(x+(1/6))(x-(5/7))
move the denominator of the fraction in front of the x
(6x+1)(7x-5)
42x^2-30x+7x-5</PRE>