Question 1067731
<pre>1/x - 1/x+b = 1/a -  1/a+b</pre>


{{{1/x - 1/(x+b) = 1/a -  1/(a+b)}}}


Use your already-learned skills with fractions, and you should find along the way,  {{{x(x+b)=a(a+b)}}}, from which you should be able to finish and solve for x.


{{{x^2+bx-a(a+b)=0}}}


{{{x=(-b+- sqrt(b^2+4a(a+b)))/2}}}