Question 1067525
{{{ 3x^4 - 2x^2 - 16 = 0 }}}
{{{  (x^2 + 2)(3x^2 - 8) = 0 }}}
--
Solutions are:
{{{  x^2+2 = 0 }}}  and {{{ 3x^2 - 8 = 0 }}}

{{{ x^2+2 = 0}}} —> {{{x^2 = -2 }}} —>  {{{ x = 0 +- sqrt(2)i }}}    (imaginary numbers)

{{{ 3x^2 - 8 = 0}}} —> {{{ 3x^2 = 8 }}} —>  {{{ x = 0 +- sqrt(8/3) }}}

( I had to place a 0 +- in there to get the format to work for plus/minus )