Question 1067495
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asolve for X by completeting the square

x^2-10x+3=0
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<pre>
x^2 - 10x + 3 = 0

is equivalent to

(x^2 - 10x + 25) - 25 + 3 = 0

is equivalent to

{{{(x-5)^2}}} - 22 = 0

is equivalent to

{{{(x-5)^2}}} = 22

is equivalent to

x-5 = +/- {{{sqrt(22)}}}

is equivalent to

x = {{{5 +- sqrt(22)}}}.


The two roots are {{{x[1]}}} = {{{5 + sqrt(22)}}}  and  {{{x[2]}}} = {{{5 - sqrt(22)}}}.
</pre>

Solved.