Question 1067407
Whichever placement of the right angle, the hypotenuse will be the segment PQ, and this length is {{{sqrt((-3-1)^2+(6-4)^2)=sqrt(16+4)=sqrt(20)=2sqrt(5)}}}.


Pick the x coordinate 1 and the y coordinate 6 for the right angle point at (1,6) and this should be the point opposite the hypotenuse in quadrant 1.