Question 1067278
 x varies inversely with the square of y; 
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k is a proportionality constant.
{{{x=k/y^2}}}



x = 6 when y = 4.
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{{{k/y^2=x}}}


{{{k=xy^2}}}


GIVEN:  {{{system(x=6,y=4)}}}


{{{k=6*4^2}}}


{{{k=6*16}}}


{{{k=96}}}


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{{{highlight(x=96/y^2)}}}