Question 1067279
pierre folded a square piece of paper vertically to make two rectangles. each rectangled had a perimeter of 39 inches. how long is each side of the original square? what is the area of the original square? what is the area of one of the rectangles? 
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Area of the square = x^2
Diameter = sqrt(2)x is the hypotenuse of each of the resulting triangles.
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Sides of one of the triangles.
x, x, sqrt(2)x
Equation:
x + x + sqrt(2)x = 39
2x + sqrt(2)x - 39 = 0
(2+sqrt(2))x = 39
x = 39/3.414
x = 11.42
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Ans: Area = 11.42*2 = 130.48
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Cheers,
Stan H.
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