Question 93699
7x^2+34x-5

Here we apply quadratic formula

x= -b+or- sqrt of b^2 -4ac/2a

here a = 7 , b= 34 , c= -5

 ==> -34 +/- sqrt of (34)^2-( 4*7*-5)/2*7

==> -34 +/- sqrt of 1156+140/14

==> -34+/- sqrt of 1296/14

==> -34 +/- 36/14

==> 2( -17 +/- 18)/2*7  ( 2 is taken as common factor)

==>-17 +/- 18 /7     ( 2  in the numerator and denominator gets cancelled)

 x = -17 + 18/ 7 and -17 -18/7

 x = 1/7 and x = -35/7 = -5

Hence the solution for x= 1/7 and -5