Question 1067136
We have 3 different coins to choose from: P, N and D.
Each time we pull 4 coins in total. 
Order is not important and repetition is allowed (that is, we can have multiple of each kind).
Therefore the total number of possible combinations is 
{{{((4+3-1)!) / (4!*(3-1)!) = 15}}}
These are:
P	P	P	P
P	P	P	N
P	P	P	D
P	P	N	N
P	P	D	D
P	P	N	D
P	N	N	N
P	D	D	D
P	N	N	D
P	N	D	D
N	N	N	N
N	N	N	D
N	N	D	D
D	D	D	D
D	D	D	N

and the respective amounts are:

4
8
13
12
22
17
16
31
21
26
20
25
30
40
35