Question 1067144
Let {{{ w }}} = the width
{{{ 2w }}} = the length
I assume the kennel is a retangle
The perimeter of a rectangle is:
{{{ 2l + 2w = 2*(2w) + 2w }}}
{{{ 2l + 2w = 6w }}}
You are given that:
{{{ 6w = 30 }}}
{{{ w = 5 }}}
and
{{{ 2w = 10 }}}
and
{{{ 5*10 = 50 }}}
the area is 50 ft2